Convert string to date, format: “dd.mm.yyyy”

Question

D <- \"06.12.1948\"                 # which is dd.mm.yyyy
as.Date(D, \"%d.%m.%y\")            # convert to date
[1] \"2019-12-06\"                  # ????    
         


        

Answer 1

To avoid remembering formats of the date we can use packaged solutions.

1) With lubridate

lubridate::dmy(D)
#[1] "1948-12-06"

2) Using anytime

anytime::anydate(D)
#[1] "1948-06-12"