Java, Long.parse binary String

Question

Why does this code throw a NumberFormatException :

String binStr = \"1000000000000000000000000000000000000000000000000000000000000000\";
System         


        

Answer 1

Largest long value is actually:

0111111111111111111111111111111111111111111111111111111111111111b = 9223372036854775807