Java, Long.parse binary String

Question

Why does this code throw a NumberFormatException :

String binStr = \"1000000000000000000000000000000000000000000000000000000000000000\";
System         


        

Answer 1

Because it's out of range. 1000...000 is 2⁶³, but Long only goes up to 2⁶³ - 1.