How can I instantiate a generic type in Java?

Question

I\'ve added a human-readable configuration file to my app using java.util.Properties and am trying to add a wrapper around it to make type conversions easier. Specifically,

Answer 1

Due to type erasure, you can't instantiate generic objects. Normally you could keep a reference to the Class object representing that type and use it to call newInstance(). However, this only works for the default constructor. Since you want to use a constructor with parameters, you'll need to look up the Constructor object and use it for the instantiation:

protected  T getProperty(String key, T fallback, Class clazz) {
    String value = properties.getProperty(key);

    if (value == null) {
        return fallback;
    } else {

        //try getting Constructor
        Constructor constructor;
        try {
            constructor = clazz.getConstructor(new Class[] { String.class });
        }
        catch (NoSuchMethodException nsme) {
            //handle constructor not being found
        }

        //try instantiating and returning
        try {
            return constructor.newInstance(value);
        }
        catch (InstantiationException ie) {
            //handle InstantiationException
        }
        catch (IllegalAccessException iae) {
            //handle IllegalAccessException
        }
        catch (InvocationTargetException ite) {
            //handle InvocationTargetException
        }
    }
}

However, seeing how much trouble it is to achieve this, including the performance cost of using reflection, it's worth looking into other approaches first.

If you absolutely need to take this route, and if T is limited to a distinct set of types known at compile time, a compromise would be to keep a static Map of Constructors, which is loaded at startup - that way you don't have to dynamically look them up at every call to this method. For example a Map> or Map, Constructor>, which is populated using a static block.