Count frequency of item in a list of tuples

Question

I have a list of tuples as shown below. I have to count how many items have a number greater than 1. The code that I have written so far is very slow. Even if there are arou

Answer 1

Let me give you an example to make you understand.Although this example is very much different than your example, I found it very helpful while solving these type of questions.

from collections import Counter

a = [
(0, "Hadoop"), (0, "Big Data"), (0, "HBase"), (0, "Java"),
(1, "Postgres"), (2, "Python"), (2, "scikit-learn"), (2, "scipy"),
(2, "numpy"), (2, "statsmodels"), (2, "pandas"), (3, "R"), (3, "Python"),
(3, "statistics"), (3, "regression"), (3, "probability"),
(4, "machine learning"), (4, "regression"), (4, "decision trees"),
(4, "libsvm"), (5, "Python"), (5, "R"), (5, "Java"), (5, "C++"),
(5, "Haskell"), (5, "programming languages"), (6, "statistics"),
(6, "probability"), (6, "mathematics"), (6, "theory"),
(7, "machine learning"), (7, "scikit-learn"), (7, "Mahout"),
(7, "neural networks"), (8, "neural networks"), (8, "deep learning"),
(8, "Big Data"), (8, "artificial intelligence"), (9, "Hadoop"),
(9, "Java"), (9, "MapReduce"), (9, "Big Data")
]
# 
# 1. Lowercase everything
# 2. Split it into words.
# 3. Count the results.

dictionary = Counter(word for i, j in a for word in j.lower().split())

print(dictionary)

# print out every words if the count > 1
[print(word, count) for word, count in dictionary.most_common() if count > 1]

Now this is your example solved in the above manner

from collections import Counter
a=[('example',123),('example-one',456),('example',987),('example2',987),('example3',987)]

dict = Counter(word for i,j in a for word in i.lower().split() )

print(dict)

[print(word ,count) for word,count in dict.most_common() if count > 1  ]