Find line number of function call from sourcing file

Question

I\'m trying to find a way to find out what file and line number a function was called from. The function is in a library file which is being sourced by my script.

Answer 1

Inspired by @nosid and @Wrikken I wrote a small function to put current stack trace into a variable called $STACK. It might be useful to output to user the location some error has happened. Too bad bash does not have a built-in printStackTrace... Hope somebody could find it handy in their projects.

function get_stack () {
   STACK=""
   local i message="${1:-""}"
   local stack_size=${#FUNCNAME[@]}
   # to avoid noise we start with 1 to skip the get_stack function
   for (( i=1; i<$stack_size; i++ )); do
      local func="${FUNCNAME[$i]}"
      [ x$func = x ] && func=MAIN
      local linen="${BASH_LINENO[$(( i - 1 ))]}"
      local src="${BASH_SOURCE[$i]}"
      [ x"$src" = x ] && src=non_file_source

      STACK+=$'\n'"   at: "$func" "$src" "$linen
   done
   STACK="${message}${STACK}"
}

Update: I fixed a typo and added an error message parameter. So first parameter of the function is an error message to be added to the stack trace. btw if your script supplied on bash's stdin (a bad idea in most cases), then the first position would be lost. If needed, then inthe for loop, change it to i<$stack_size + 1. But as I said, it is not good idea to feed your script to bash`s stdin, here's why.

Update 2: I found I have an older answer about this. Thought to better keep updated version of the code in one place. So decided to make a gist. Feel free to suggest improvements to the gist. I'll try to keep this answer updated if any changes occur but I can't guarantee.