Is the C# “explicit implementation” of the interface present in Java?

Question

In C#, if you have two base interfaces with the same method (say, F()) you can use explicit implementation to perform different impl. for F(). This alloes you to differently

Answer 1

You can achieve similar effect using the mechanism of anonymous interface implementation in Java.

See example:

interface Foo {

    void f();
}

interface Bar {

    void f();
}

public class Test {

    private String foo = "foo", bar = "bar";

    Foo getFoo() {
        return new Foo() {

            @Override
            public void f() {
                System.out.println(foo);
            }
        };
    }

    Bar getBar() {
        return new Bar() {

            @Override
            public void f() {
                System.out.println(bar);
            }
        };
    }

    public static void main(String... args) {
        Test test = new Test();
        test.getFoo().f();
        test.getBar().f();
    }
}