How to continue executing code after calling ShowDialog()

Question

the Form.ShowDialog() method causes the code to be halted until the newly called form is closed. I need the code to continue running after the ShowDialog() method is called.

Answer 1

As long as you do asynchronous operations during the time that the modal dialog is opened, you can do it as simply as shown below, assuming button1_Click() is the event handler for a button.

private async void button1_Click(object sender, EventArgs e)
{
    // create and display modal form
    Form2 modalForm = new Form2();
    BeginInvoke((Action)(() => modalForm.ShowDialog()));

    // do your async background operation
    await DoSomethingAsync();

    // close the modal form
    modalForm.Close();
}


private async Task DoSomethingAsync()
{
    // example of some async operation....could be anything
    await Task.Delay(10000);
}

I found that when I used the solution that suggested to use Show(), I could end up in cases where the dialog I wanted to be modal would end up behind the main form, after switching back and forth between apps. That never happens when I use the solution above.