The question is as given in the title, ie, to access element whose parent is hidden. The problem is that, as per the cypress.io docs :
An element is
I came across this topic but was not able to run your example. So I tried a bit and my final solution is this. maybe someone other also needs this. Please note that I use typescript.
First: Define a custom command
Cypress.Commands.add("isVisible", { prevSubject: true}, (p1: string) => {
cy.get(p1).should((jq: JQuery) => {
if (!jq || jq.length === 0) {
//assert.fail(); seems that we must not assetr.fail() otherwise cypress will exit immediately
return;
}
const elem: HTMLElement = jq[0];
const doc: HTMLElement = document.documentElement;
const pageLeft: number = (window.pageXOffset || doc.scrollLeft) - (doc.clientLeft || 0);
const pageTop: number = (window.pageYOffset || doc.scrollTop) - (doc.clientTop || 0);
let elementLeft: number;
let elementTop: number;
let elementHeight: number;
let elementWidth: number;
const length: number = elem.getClientRects().length;
if (length > 0) {
// TODO: select correct border box!!
elementLeft = elem.getClientRects()[length - 1].left;
elementTop = elem.getClientRects()[length - 1].top;
elementWidth = elem.getClientRects()[length - 1].width;
elementHeight = elem.getClientRects()[length - 1].height;
}
const val: boolean = !!(
elementHeight > 0 &&
elementWidth > 0 &&
elem.getClientRects().length > 0 &&
elementLeft >= pageLeft &&
elementLeft <= window.outerWidth &&
elementTop >= pageTop &&
elementTop <= window.outerHeight
);
assert.isTrue(val);
});
});
Please note the TODO. In my case I was targeting a button which has two border boxes. The first with height and width 0. So i must select the second one. Please adjust this to your needs.
Second: Use it
cy.wrap("#some_id_or_other_locator").isVisible();