Scala: curried constructors

Question

I have the following Scala class:

class Person(var name : String, var age : Int, var email : String)

I would like to use the Person constru

Answer 1

A bit late to this party, but if you make Person a case class:

scala> case class Person(name: String, age: Int, email: String)
defined class Person

Scala generates a companion object containing Person.apply(String, Int, String) and some other stuff for you. Then you can do:

scala> Person.curried
res5: String => (Int => (String => Person)) = 

Which is shorthand for:

(Person.apply _).curried

It works with var parameters too.