Difference between SHL and SAL in 80x86

Question

I have learned how to work with 80x86 assembler, so in bit-wise shift operation, I faced a problem with SAL and SHL usage. I means the difference between lines of code as fo

Answer 1

I would also have a look at the table in the Intel 64 and IA-32 Architectures Software Developer's Manuals Volume 2 "SAL/SAR/SHL/SHR—Shift" which contains a table with:

D0 /4             SHL r/m8, 1
REX + D0 /4       SHL r/m8**, 1
D2 /4             SHL r/m8, CL
REX + D2 /4       SHL r/m8**, CL
C0 /4 ib          SHL r/m8, imm8
REX + C0 /4 ib    SHL r/m8**, imm8
D1 /4             SHL r/m16,1
D3 /4             SHL r/m16, CL
C1 /4 ib          SHL r/m16, imm8
D1 /4             SHL r/m32,1
REX.W + D1 /4     SHL r/m64,1
D3 /4             SHL r/m32, CL
REX.W + D3 /4     SHL r/m64, CL
C1 /4 ib          SHL r/m32, imm8
REX.W + C1 /4 ib  SHL r/m64, imm8

D0 /4             SAL r/m8, 1
REX + D0 /4       SAL r/m8**, 1
D2 /4             SAL r/m8, CL
REX + D2 /4       SAL r/m8**, CL
C0 /4 ib          SAL r/m8, imm8
REX + C0 /4 ib    SAL r/m8**, imm8
D1 /4             SAL r/m16, 1
D3 /4             SAL r/m16, CL
C1 /4 ib          SAL r/m16, imm8
D1 /4             SAL r/m32, 1
REX.W + D1 /4     SAL r/m64, 1
D3 /4             SAL r/m32, CL
REX.W + D3 /4     SAL r/m64, CL
C1 /4 ib          SAL r/m32, imm8
REX.W + C1 /4 ib  SAL r/m64, imm8

By comparing both parts, we see that each operand choice has the same encoding for both SHL and SAL, so they are identical.

Mystical's quote follows in the same section further confirming it.