Two conditions in a bash if statement

Question

I\'m trying to write a script which will read two choices, and if both of them are \"y\" I want it to say \"Test Done!\" and if one or both of them isn\'t \"y\" I want it to

Answer 1

You are checking for the wrong condition.

if [ "$choice" != 'y' ] && [ "$choice1" != 'y' ];

The above statement is true when choice!='y' and choice1!='y', and so the program correctly prints "Test Done!".

The corrected script is

echo "- Do You want to make a choice ?"
read choice

echo "- Do You want to make a choice1 ?"
read choice1

if [ "$choice" == 'y' ] && [ "$choice1" == 'y' ]; then
    echo "Test Done !"
else
    echo "Test Failed !"
fi