how to find muliplication of large numbers modulo 100000007

后端 未结 3 1805
我寻月下人不归
我寻月下人不归 2020-12-17 08:05

As we know 1000000007 is a large prime number. How can I find multiplication of two large numbers modulo 1000000007

For example if I want to find 78627765*67527574 m

3条回答
  •  一向
    一向 (楼主)
    2020-12-17 08:44

    Why don't you want to use 64-bit arithmetic for that ? Of course this only works if the operands being multplied do not exceed 32 bits each (but this can also be fixed). Consider:

    typedef unsigned long long uint64;
    uint64 m = 1000000007UL;
    uint64 r = (uint64)a * (uint64)b;
    r = r % m; // get the residue
    

    One can also optimize it to avoid '%' which might be expensive:

    double inv = 1.0 / 1000000007UL; // precompute inverse
    uint64 r = (uint64)a * (uint64)b;
    uint64 rf = (uint64)floor((double)a * (double)b * inv); // floor(a * b / m) 
    r = r - rf * m; //  residue
    

    Note that the second method may require some playing around with accuracy. You can also use 'long double' instead

提交回复
热议问题