best approach for jQuery slider with dynamic prev/next content?

Question

Here\'s a somewhat complex puzzle, I\'d love some feedback on how others would approach this.

<

Answer 1

You have two options in my opinion:

1. Populate each slider on page load so that a jQuery click function animates the content
2. Populating the data on a per slide basis using an AJAX call

If it's only a few items/slides, then I'd populate on page load. If you're looking at lots of slides (which you might expect with a daily news blog) or if each slide will contain a lot of data (such as high-res images, etc.) I'd go with the second option.

The second option is easy to do. All you'd need is three divs (one for the onscreen slide and two for the flanking offscreen slides that will 'replace' the onscreen one when either arrow is clicked). I'd use something like this:

And the required CSS:

.container{width:200px;height:150px;overflow:hidden}
.inner-container{width:600px;height:150px;margin-left:-200px}
.content{float:left;width:200px;height:150px}

And as for jQuery:

$(".next").live('click', function(){
  var current_id=$(this).prev(".on_screen").attr("id"); // get current page ID
  $(".content").css("float","right"); // float all elements to the right
  $(".off_screen_right").animate({display:none;}); // make the furthest right disappear gradually
  $(".on_screen").attr("class","off_screen_right"); // make on_screen the new off_screen_right and add the correct ID attribute
  $(".off_screen_left").attr("class","content on_screen"); // make off_screen_left the new on_screen
  $(".container").prepend('
'); // add the new off_screen_left element and add the correct ID attribute
  $(".off_screen_left").load("load-content.php?page_id="+current_id-1);  // populate the new off_screen_left element
});
$(".back").live('click', function(){
  var current_id=$(this).next(".on_screen").attr("id"); // get current page ID
  $(".content").css("float","left"); // float all elements to the left
  $(".off_screen_left").animate({display:none;}); // make the furthest left disappear gradually
  $(".on_screen").attr("class","off_screen_left"); // make on_screen the new off_screen_left and add the correct ID attribute
  $(".off_screen_right").attr("class","content on_screen"); // make off_screen_right the new on_screen
  $(".container").append('
'); // add the new off_screen_left element and add the correct ID attribute
  $(".off_screen_right").load("load-content.php?page_id="+current_id+1);  // populate the new off_screen_left element
});

But that's just one option. You can use a slider out of the box but I prefer to custom code things so that I know exactly what I'm doing.