How to replace a node-name with another in Xslt?

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渐次进展 2020-12-17 05:34

Bad wording on the question, sorry about that. Will try to explain what I\'m trying to do. Basically I have the output from a search as Xml and in that Xml there is a node l

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  •  孤城傲影
    2020-12-17 06:04

    This should do what you need. It uses the apply template instead of calling templates and is more of a functional way to tackle this problem.

    
        
        
            
        
    
        
        
          
            
          
        
    
    

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