Typedeffing a function (NOT a function pointer)

Question

typedef void int_void(int);

int_void is a function taking an integer and returning nothing.

My question is: can it be

Answer 1

This should work, no casting required:

void f(int x) { printf("%d\n", x); }

int main(int argc, const char ** argv)
{
    typedef void (*int_void)(int);
    int_void test = f;
    ...
 }

A function's name "devolves" into a function pointer anytime you use the function's name in something other than a function call. If is is being assigned to a func ptr of the same type, you don't need a cast.

The original

typedef int_void(int);

is not useful by itself, without using a pointer to the type. So the answer to your question is "no, you can't use that typedef without a pointer".