How to get age in years,months and days using Oracle

Question

I\'m trying to print for each person its age using this format :

E.g : 19 years , 8 months , 13 days.

I\'ve googled a lot and I\'ve noticed that there is a s

Answer 1

Syntax:

SELECT 
  CONCAT(
    TIMESTAMPDIFF(YEAR, ?, NOW()),
    ' Years,',
    TIMESTAMPDIFF(MONTH, ?, NOW()) % 12,
    ' Months,',
    FLOOR(TIMESTAMPDIFF(DAY, ?, NOW()) % 30.4375),
    ' Days'
  ) AS age 
FROM
  DUAL

• Input: replace '?' with Date of Birth. For Example, '1994-07-08'
• Output: This query will return age in 'X' Years 'Y' Months and 'Z' days.