Java: “Local variable may not have been initialized” not intelligent enough?

Question

Consider the following method:

void a ()
{
    int x;
    boolean b = false;
    if (Math.random() < 0.5)
    {
        x = 0;
        b = true;
    }
            


        

Answer 1

There is one :

void a () {
    if (Math.random() < 0.5) {
        int x = 1;
    }
}

The compiler isn't responsible for devising and testing the algorithm. You are.

But maybe you should propose a more practical use case. Your example doesn't really show what's your goal.