How to work with the bits in a byte

Question

I have a single byte which contains two values. Here\'s the documentation:

The authority byte is split into two fields. The three least significant bits

Answer 1

Your use of the BitArray is incorrect. This:

BitArray BA = new BitArray(mybyte);

..will be implicitly converted to an int. When that happens, you're triggering this constructor:

BitArray(int length);

..therefore, its creating it with a specific length.

Looking at MSDN (http://msdn.microsoft.com/en-us/library/x1xda43a.aspx) you want this:

BitArray BA = new BitArray(new byte[] { myByte });

Length will then be 8 (as expected).