JavaScript anagram comparison

Question

I\'m trying to compare two strings to see if they are anagrams.

My problem is that I\'m only comparing the first letter in each string. For example, \"Mary\" and \"

Answer 1

Here's my contribution, I had to do this exercise for a class! I'm finally understanding how JS works, and as I was able to came up with a solution (it's not - by far - the best one, but it's ok!) I'm very happy I can share this one here, too! (although there are plenty solutions here already, but whatever :P )

function isAnagram(string1, string2) {
    // first check: if the lenghts are different, not an anagram 
    if (string1.length != string2.length)
        return false
    else {
    // it doesn't matter if the letters are capitalized, 
    // so the toLowerCase method ensures that...
        string1 = string1.toLowerCase()
        string2 = string2.toLowerCase()
        
    // for each letter in the string (I could've used for each :P)
        for (let i = 0; i < string1.length; i++) {
            // check, for each char in string2, if they are NOT somewhere at string1
            if (!string1.includes(string2.charAt(i))) {
                return false
            }
            else {
                // if all the chars are covered 
                // and the condition is the opposite of the previous if
                if (i == (string1.length - 1))
                    return true
            }
        }
    }
}