I\'m trying to compare two strings to see if they are anagrams.
My problem is that I\'m only comparing the first letter in each string. For example, \"Mary\" and \"
A more modern solution without sorting.
function(s, t) { if(s === t) return true if(s.length !== t.length) return false let count = {} for(let letter of s) count[letter] = (count[letter] || 0) + 1 for(let letter of t) { if(!count[letter]) return false else --count[letter] } return true; }