Why is R dplyr::mutate inconsistent with custom functions

Question

This question is a \"why\", not a how. In the following code I\'m trying to understand why dplyr::mutate evaluates one custom function (f()) with t

Answer 1

We can loop through each element of 'a' using map and apply the function f

library(tidyverse)
df %>%
    mutate(asq = a^2, fout = map_dbl(a, f), gout = g(a)) 
#    a   asq        fout       gout
#1   0     0    10.88874  0.0000000
#2  10   100  1010.88874 -0.5440211
#3 100 10000 10010.88874 -0.5063656