frame with 10 rows and 3 columns
a b c 1 1 201 1 2 2 202 1 3 3 203 1 4 4 204 1 5 5 205 4 6 6 206 5 7 7 207 4 8 8 208 4 9 9 209 8 10 1
Building on Joshua's answer:
Data[Data$c %in% names(which(table(Data$c) > 2)), ]