Convert single char to int

Question

How can I convert char a[0] into int b[0] where b is a empty dynamically allocated int array

I have tried

char a[] = \"4x^0\";
int *b;
b = new int[10         


        

Answer 1

The atoi() version isn't working because atoi() operates on strings, not individual characters. So this would work:

char a[] = "4";
b[0] = atoi(a);

Note that you may be tempted to do: atoi(&temp) but this would not work, as &temp doesn't point to a null-terminated string.