Save argv to vector or string

Question

I need to save all arguments to a vector or something like this. I\'m not a programmer, so I don\'t know how to do it, but here\'s what I\'ve got so far. I just want to call

Answer 1

To build string with all argument concatenated and then run a command based on those arguments, you can use something like:

#include 
using namespace std;
string concatenate ( int argc, char* argv[] )
{
    if (argc < 1) {
        return "";
    }
    string result(argv[0]);
    for (int i=1; i < argc; ++i) {
        result += " ";
        result += argv[i];
    }
    return result;
}
int main ( int argc, char* argv[] )
{
    const string arguments = concatenate(argc-1, argv+1);
    if (arguments == "/all /renew") {
        const string program = "c:\\windows\\system32\\ipconfig.exe";
        const string command = program + " " + arguments;
        system(command.c_str());
    } else {
        system("\"\"c:\\program files\\internet explorer\\iexplore.exe\" \"www.stackoverflow.com\"\"");
    }
}