I have a std::vector of this struct:
struct MS
{
double aT;
double bT;
double cT;
};
which I want to use std::sort on aswell
I had the same problem for std::equal_range and came up with an alternative solution.
I have a collection of pointers to objects sorted on a type field. I need to find the find the range of objects for a given type.
const auto range = std::equal_range (next, blocks.end(), nullptr,
[type] (Object* o1, Object* o2)
{
return (o1 ? o1->Type() : type) < (o2 ? o2->Type() : type);
});
Although it is less efficient than a dedicated predicate as it introduces an unnecessary nullptr test for each object in my collection, it does provide an interesting alternative.
As an aside, when I do use a class as in your example, I tend to do the following. As well as being shorter, this allows me to add additional types with only 1 function per type rather then 4 operators per type.
class MSbTLess
{
private:
static inline const double& value (const MS& val)
{
return val.bT;
}
static inline const double& value (const double& val)
{
return val;
}
public:
template
bool operator() (const T1& lhs, const T2& rhs) const
{
return value (t1) < value (t2);
}
};