Getting captured group in one line

Question

There is a known \"pattern\" to get the captured group value or an empty string if no match:

match = re.search(\'regex\', \'text\')
if match:
    value = mat         


        

Answer 1

You can do it as:

value = re.search('regex', 'text').group(1) if re.search('regex', 'text') else ''

Although it's not terribly efficient considering the fact that you run the regex twice.

Or to run it only once as @Kevin suggested:

value = (lambda match: match.group(1) if match else '')(re.search(regex,text))