Get next N elements from enumerable

Question

Context: C# 3.0, .Net 3.5
Suppose I have a method that generates random numbers (forever):

private static IEnumerable RandomNumberGenerator(         


        

Answer 1

I had made some mistakes in my original answer but some of the points still stand. Skip() and Take() are not going to work the same with a generator as it would a list. Looping over an IEnumerable is not always side effect free. Anyway here is my take on getting a list of slices.

    public static IEnumerable RandomNumberGenerator()
    {
        while(true) yield return random.Next();
    }

    public static IEnumerable> Slice(this IEnumerable enumerable, int size, int count)
    {
        var slices = new List>();
        foreach (var iteration in Enumerable.Range(0, count)){
            var list = new List();
            list.AddRange(enumerable.Take(size));
            slices.Add(list);
        }
        return slices;
    }