Can I initialize an array using the std::initializer_list instead of brace-enclosed initializer?

Question

Can I initialize an array using the std::initializer_list object instead of brace-enclosed initializer?

As known, we can do this: http://en.cppreference

Answer 1

As far I know, no: you can't initialize a std::array with a std::initializer_list.

The problem is that std::array is intended as a lightweight replacement (a wrapper) for the classic C-style array. So light that is without constructors, so only implicit constructor can be used.

The construction with aggregate initialization (via implicit constructor) is possible because it's possible for the C-style array.

But std::initializer_list is a class, more complicated than an aggregate inizialization.

You can initialize, by example, a std::vector with a std::initializer_list but only because there is an explicit constructor, for std::vector, that receive a std::initializer_list. But std::vector is a heavier class.

The only solution that I see is a 2 step way: (1) construction and (2) copy of the std::initializer_list values. Something like

std::array arr5;

auto  ui = 0U;
auto  cit = il.cbegin();

while ( (ui < arr5.size()) && (cit != il.cend()) )
   arr5[ui++] = *cit++;

p.s.: sorry for my bad English.