Unexpected $end in eval()'d code

Question

I hate to ask such a specific question, but I\'m getting an error I can\'t figure out. This is in a cron job which runs on the hour. I\'m creating an array of tasks, each of

Answer 1

You are missing ';' on end of string evaluation. Eval function able to process statements or expressions.

Example:

$value = 7;
eval("\$value+=2;");
echo $value;