java- how to generate a random hexadecimal value within specified range of values

前端 未结 6 396
广开言路
广开言路 2020-12-16 14:40

I have a scenario in a java web app, where a random hexadecimal value has to be generated. This value should be within a range of values specified by me. (The range of value

6条回答
  •  感情败类
    2020-12-16 15:05

    Yes, you just generate a decimal value in your range. Something such as:

    Random rand = new Random();
    int myRandomNumber = rand.nextInt(0x10) + 0x10; // Generates a random number between 0x10 and 0x20
    System.out.printf("%x\n",myRandomNumber); // Prints it in hex, such as "0x14"
    // or....
    String result = Integer.toHexString(myRandomNumber); // Random hex number in result
    

    Hex and decimal numbers are handled the same way in Java (as integers), and are just displayed or inputted differently. (More info on that.)

提交回复
热议问题