C: finding the number of elements in an array[]

Question

In C: How do you find the number of elements in an array of structs, after sending it to a function?

int main(void) {
  myStruct array[] = { struct1, struct2         


        

Answer 1

As an example to your solution:

Given

struct contain {
char* a;        //
int allowed;    //

struct suit {
   struct t {
          char* option;
          int count;
   } t;

   struct inner {
          char* option;
          int count;
   } inner;
} suit;
};

// eg. initialized

     struct contain structArrayToBeCheck[] = {
    {
        .a = "John",
        .allowed = 1,

        .suit = {
            .t = {
                .option = "ON",
                .count = 7
            },

            .inner = {
                .option = "OFF",
                .count = 7
            }
        }
    },
    {
        .a = "John",
        .allowed = 1,

        .suit = {
            .t = {
                .option = "ON",
                .count = 7
            },

            .inner = {
                .option = "OFF",
                .count = 7
            }
        }
    },
    {
        .a = "John",
        .allowed = 1,

        .suit = {
            .t = {
                .option = "ON",
                .count = 7
            },

            .inner = {
                .option = "OFF",
                .count = 7
            }
        }
    },
    {
        .a = "John",
        .allowed = 1,

        .suit = {
            .t = {
                .option = "ON",
                .count = 7
            },

            .inner = {
                .option = "OFF",
                .count = 7
            }
        }
    }

};

in main()

printf("Number of Struct within struct array: %d \n", sizeof(structArrayToBeCheck)/sizeof(struct contain));

gives you the correct answer.