R: data.table count !NA per row

Question

I am trying to count the number of columns that do not contain NA for each row, and place that value into a new column for that row.

Example data:

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Answer 1

Try this one using Reduce to chain together + calls:

d[, num_obs := Reduce(`+`, lapply(.SD,function(x) !is.na(x)))]

If speed is critical, you can eek out a touch more with Ananda's suggestion to hardcode the number of columns being assessed:

d[, num_obs := 4 - Reduce("+", lapply(.SD, is.na))]

Benchmarking using Ananda's larger data.table d from above:

fun1 <- function(indt) indt[, num_obs := rowSums(!is.na(indt))][]
fun3 <- function(indt) indt[, num_obs := Reduce(`+`, lapply(.SD,function(x) !is.na(x)))][]
fun4 <- function(indt) indt[, num_obs := 4 - Reduce("+", lapply(.SD, is.na))][]

library(microbenchmark)
microbenchmark(fun1(copy(d)), fun3(copy(d)), fun4(copy(d)), times=10L)

#Unit: milliseconds
#          expr      min       lq     mean   median       uq      max neval
# fun1(copy(d)) 3.565866 3.639361 3.912554 3.703091 4.023724 4.596130    10
# fun3(copy(d)) 2.543878 2.611745 2.973861 2.664550 3.657239 4.011475    10
# fun4(copy(d)) 2.265786 2.293927 2.798597 2.345242 3.385437 4.128339    10