Why is there no ^^ operator in C/C++?

Question

& has &&. | has ||. Why doesn\'t ^ have ^^?

I understand that it wouldn\'t

Answer 1

Technically, one already exists:

a != b

since this will evaluate to true if the truth value of the operands differ.

Edit:

Volte's comment:

(!a) != (!b)

is correct because my answer above does not work for int types. I will delete mine if he adds his answer.

Edit again:

Maybe I'm forgetting something from C++, but the more I think about this, the more I wonder why you would ever write if (1 ^ 2) in the first place. The purpose for ^ is to exclusive-or two numbers together (which evaluates to another number), not convert them to boolean values and compare their truth values.

This seems like it would be an odd assumption for a language designer to make.