Given two lists of dictionaries:
>>> lst1 = [{id: 1, x: \"one\"},{id: 2, x: \"two\"}]
>>> lst2 = [{id: 2, x: \"two\"}, {id: 3, x: \"three\"
One possible way to define it:
lst1 + [x for x in lst2 if x not in lst1]
Out[24]: [{'id': 1, 'x': 'one'}, {'id': 2, 'x': 'two'}, {'id': 3, 'x': 'three'}]
Note that this will keep both {'id': 2, 'x': 'three'} and {'id': 2, 'x': 'two'} as you did not define what should happen in that case.
Also note that the seemingly-equivalent and more appealing
set(lst1 + lst2)
will NOT work since dicts are not hashable.