Why it is implied that objects are equal if compareTo() returns 0?

Question

Let\'s have a class Person. Person has a name and height.

Equals and hashCode() takes into account only name. Person is comparable (or we implement co

Answer 1

you can fix it by using name for another comparison when the heights are equal

@Override
public int compareTo(Person o) {
    if(height == o.height)return name.compareTo(o.name);

    return Integer.compare(height, o.height);
}

since names are unique this will only return 0 if this.equals(o)