Starting with
OrderedDict([(\'a\', 1), (\'c\', 3), (\'b\', 2)])
is it possible to end up with
OrderedDict([(\'a\', 1), (\'_
You could try:
>>> d = OrderedDict([('a', 1), ('c', 3), ('b', 2)]) >>> d OrderedDict([('a', 1), ('c', 3), ('b', 2)]) >>> d2 = OrderedDict([('__C__', v) if k == 'c' else (k, v) for k, v in d.items()]) >>> d2 OrderedDict([('a', 1), ('__C__', 3), ('b', 2)])