Differentiate String Literal from Char Array

Question

I want to write some function that takes a string literal - and only a string literal:

template 
void foo(const char (&s         


        

Answer 1

You can use user-defined literals, that by definitions can only be applied to literals:

#include 

struct literal_wrapper
{
    const char* const ptr;
private:
    constexpr literal_wrapper(const char* p) : ptr(p) {}
    friend constexpr literal_wrapper operator "" _lw(const char* p, std::size_t);
};
constexpr literal_wrapper operator "" _lw(const char* p, std::size_t){ return literal_wrapper(p); }

literal_wrapper f()
{
    std::cout << "f()" << std::endl;
    return "test"_lw;
}

void foo(const literal_wrapper& lw)
{
    std::cout << "foo:" << lw.ptr << " " << static_cast(lw.ptr) << std::endl;
}

int main()
{
    auto x1 = f(), x2 = f(), x3 = f();
    const void* p1 = x1.ptr;
    const void* p2 = x2.ptr;
    const void* p3 = x3.ptr;
    std::cout << x1.ptr << " " << p1 << " " << p2 << " " << p3 << std::endl;

    foo(x1);
    foo(x2);
    foo("test"_lw);
    foo("test2"_lw);
}