I want to use switch-case in my program but the compiler gives me this error:
switch expression of type \'QString\' is illegal
How can I us
try this:
// file qsswitch.h
#ifndef QSSWITCH_H
#define QSSWITCH_H
#define QSSWITCH(__switch_value__, __switch_cases__) do{\
const QString& ___switch_value___(__switch_value__);\
{__switch_cases__}\
}while(0);\
#define QSCASE(__str__, __whattodo__)\
if(___switch_value___ == __str__)\
{\
__whattodo__\
break;\
}\
#define QSDEFAULT(__whattodo__)\
{__whattodo__}\
#endif // QSSWITCH_H
how to use:
#include "qsswitch.h"
QString sW1 = "widget1";
QString sW2 = "widget2";
class WidgetDerived1 : public QWidget
{...};
class WidgetDerived2 : public QWidget
{...};
QWidget* defaultWidget(QWidget* parent)
{
return new QWidget(...);
}
QWidget* NewWidget(const QString &widgetName, QWidget *parent) const
{
QSSWITCH(widgetName,
QSCASE(sW1,
{
return new WidgetDerived1(parent);
})
QSCASE(sW2,
{
return new WidgetDerived2(parent);
})
QSDEFAULT(
{
return defaultWidget(parent);
})
)
}
there is some simple macro magic. after preprocessing this:
QSSWITCH(widgetName,
QSCASE(sW1,
{
return new WidgetDerived1(parent);
})
QSCASE(sW2,
{
return new WidgetDerived2(parent);
})
QSDEFAULT(
{
return defaultWidget(parent);
})
)
will work like this:
// QSSWITCH
do{
const QString& ___switch_value___(widgetName);
// QSCASE 1
if(___switch_value___ == sW1)
{
return new WidgetDerived1(parent);
break;
}
// QSCASE 2
if(___switch_value___ == sW2)
{
return new WidgetDerived2(parent);
break;
}
// QSDEFAULT
return defaultWidget(parent);
}while(0);