Find the maximum consecutive years for each ID's in a table(Oracle SQL)

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遥遥无期
遥遥无期 2020-12-16 08:17

I am trying to solve a problem of how to find the maximum count of consecutive years in a series of records. In the following example:

ID  Year
1 1993
1 1994
1 19         


        
2条回答
  •  轮回少年
    2020-12-16 09:12

    This will produce your desired result:

    select
      id,
      ayear,
      byear,
      yeardiff
    from
    (
      select
        a.id,
        a.year ayear,
        b.year byear,
        (b.year - a.year)+1 yeardiff,
        dense_rank() over (partition by a.id order by (b.year - a.year) desc) rank
      from
        years a
        join years b on a.id = b.id 
            and b.year > a.year
      where
        b.year - a.year = 
          (select count(*)-1
             from years a1
            where a.id = a1.id
                 and a1.year between a.year and b.year)
    )
    where
      rank = 1
    

    EDIT updated to display start/end years of longest stretch.

    SQLFiddle

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