When do I need to call `super` from a constructor?

Question

Reading Dr. Axel Rauschmayer\'s blog on ES6 classes, I understand that a derived class has the following default constructor when none is provided

constructo         


        

Answer 1

Yes, that sounds correct, albeit a bit oddly formulated. The rules should be

• In a derived class, you always¹ need to call the super(…) constructor
• If you are not doing more than the default constructor, you can omit the whole constructor(){}, which in turn will make your class code not contain a super call.

_{1: You don't need to call it in the suspicious edge case of explicitly returning an object, which you hardly ever would.}