Generics Java and Shadowing of type parameters

Question

This code seems to work fine

class Rule
{

    public Rule(T t)
    {

    }
    public  void Foo(T t)
    {

    }
 }
         


        

Answer 1

Does the method type parameter shadow the class type parameter?

The declaration on constructor is not referred to class type. So yes, it shadow the class type parameter.

In this case it is used as a generic type param that you can use with the constructor, for example as argument. Try this constructor:

public 
 Rule(P arg1, P arg2) {    
}

As you can see I define a type

and then I use it to be sure that the arguments will be of type P. In your case you are declaring a type that will be valid for the constructor without using it.

Look at this page.

Also when you create an object does it use the type parameter of the class?

Every generic type definition has is scope as a variable. So out of the constructor returns valid the class type.