Memory-mapped files in Java

Question

I\'ve been trying to write some very fast Java code that has to do a lot of I/O. I\'m using a memory mapped file that returns a ByteBuffer:

public static Byt         


        

Answer 1

Using the ByteBuffer.wrap() functionality does not impose a high burden. It allocates a simple object and initializes a few integers. Writing your algorithm against ByteBuffer is thus your best bet if you need to work with read only files.