How to sort ip address in ascending order

Question

Is there any method to sort this? Or do I just need to split it and use a loop to compare? Input

123.4.245.23
104.244.253.29
1.198.3.93
32.183.93.40
104.30.2         


        

Answer 1

public class IpSort {  
    public static void main(String[] args) {  
        // TODO Auto-generated method stub  
        String[] arr = {"192.168.1.1",  
            "191.122.123.112",  
            "192.161.1.1",  
            "191.122.123.1",  
            "123.24.5.78",  
            "121.24.5.78",  
            "123.24.4.78",  
            "123.2.5.78",  
            "192.1.1.1",  
            "125.45.67.89",  
            "1.1.1.1",  
            "3.4.5.6",  
            "2.2.2.2",  
            "6.6.6.7",  
            "155.155.23.0"};  
        String tmp;  
        for(int i=0;i Integer.parseInt(instr2[0]))  
                           {  
                               tmp=arr[j-1];  
                               arr[j-1]=arr[j];  
                               arr[j]=tmp;  
                           }else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) > Integer.parseInt(instr2[1]) )  
                           {  
                                tmp=arr[j-1];  
                                arr[j-1]=arr[j];  
                                arr[j]=tmp;  
                           } else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) == Integer.parseInt(instr2[1])  
                         && Integer.parseInt(instr1[2]) > Integer.parseInt(instr2[2]) )  
                           {  
                                tmp=arr[j-1];  
                                arr[j-1]=arr[j];  
                                arr[j]=tmp;  
                           } else if(Integer.parseInt(instr1[0]) == Integer.parseInt(instr2[0])  
                         && Integer.parseInt(instr1[1]) == Integer.parseInt(instr2[1])  
                         && Integer.parseInt(instr1[2]) == Integer.parseInt(instr2[2])  
                         && Integer.parseInt(instr1[3]) > Integer.parseInt(instr2[3]) )  
                           {  
                               tmp=arr[j-1];  
                               arr[j-1]=arr[j];  
                               arr[j]=tmp;  
                           }  
                  }  

        }  
        System.out.println("final sorted list of ips :\n");  
        for(int k=0;k