In C/C++, are volatile variables guaranteed to have eventually consistent semantics betwen threads?

Question

Is there any guarantee by any commonly followed standard (ISO C or C++, or any of the POSIX/SUS specifications) that a variable (perhaps marked volatile), not guarded by a m

Answer 1

If I've understood correctly the relevant sections, C++0X won't guaranteed it for standalone variable or even volatile one (volatile isn't designed for that use), but will introduce atomic types for which you'll have the guarantee (see header ).