Sorting digits of an integer

Question

You are given an integer 51234 (say) we need to sort the digits of a number the output will be 12345.

How to do it without using array ?

Answer 1

Divide by 10 given integer in loop. Print the reminder in each iteration.

Or "sort" means what here? For real sorting you will need two loops. One of them will be from 0 to 9. Another one will be that was described early.

int main()
{
    int x = 0;
    cin >> x;

    for ( int l = 0; l < 10; ++l )
    {
        int rem = x % 10;
        int tx = x / 10;
        while ( rem || tx )
        {
            if ( rem == l ) cout << rem;
            rem = tx % 10;
            tx = tx / 10;
        }
    }
    cout << endl;
}