Default value for function parameter?

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情深已故
情深已故 2020-12-16 01:17

So I\'ve been doing this for as long as I can remember, but I\'m curious if this is really what I should be doing. You write a function that takes a parameter, so you antic

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  •  误落风尘
    2020-12-16 02:13

    You can't have overloaded functions in JavaScript. Instead, use object based initialization, or check for the values and assign a default if none supplied.

    In your example, the second function foo(bar) will replace the first one.

    Here's a function using object initialization.

    function foo(config) {
        extend(this, config);
    }
    

    where extend is a function that merges the config object with the current object. It is similar to the $.extend method in jQuery, or $extend method of MooTools.

    Invoke the function and pass it named key value pairs

    foo({ bar: 0 });
    

    The other way to initialize is to look at the supplied values, and assign a default if the value is not given

    function foo(bar) {
        bar = bar || 0;
    }
    

    This works as long as bar is not a falsy value. So foo(false) or foo("") will still initialize bar to 0. For such cases, do an explicit check.

    function foo(bar) {
        bar = (typeof bar == 'undefined' ? 0 : bar);
    }
    

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