How JVM finds method (parameter with the closest matching) to call in case of function overloading

Question

The JVM decides which overloaded method to call at compile time. I have one example:

public class MainClass{

  public static void go(Long n) {System.out.pr         


        

Answer 1

The video below clearly explains the way how the JVM select one method among various eligible methods in the case of method overloading.

https://www.youtube.com/watch?v=P4XtP1aeI3g