How JVM finds method (parameter with the closest matching) to call in case of function overloading

Question

The JVM decides which overloaded method to call at compile time. I have one example:

public class MainClass{

  public static void go(Long n) {System.out.pr         


        

Answer 1

Because upcasting to int was in version 1.0 of Java and auto-boxing was added in version 5.0. Changing the behaviour would break code written for older version of Java.