SQL group by day, show orders for each day

Question

I have an SQL 2005 table, let\'s call it Orders, in the format:

OrderID, OrderDate,  OrderAmount
1,       25/11/2008, 10
2,       25/11/2008, 2
3,       30/1         


        

Answer 1

If you want to see value zero than put the following query:

select count(*), sum(OrderAmount)
from Orders
where OrderDate>getdate()-7
  and sum(OrderAmount) > 0 or sum(OrderAmount) = 0
group by datepart(day,OrderDate)